Equations of parallel and perpendicular lines

Question

The equation for line j can be written as: y-3=-4/3(x-5). Parallel to line j is line k, which passes through the point (-4,6). What is the equation of line k? Write the equation in slope-intercept form. Write the numbers in the equation as proper fractions, improper fractions, or integers.

Answer 1

k has the same slope = -4/3 = m, (h,k) = (-4,6)

plug those values into

y-h = m(x-k) the slope point form of the equation

y-6 = (-4/3)(x+4)

or

3y-18 = -4x -16

4x + 3y = 2