c is a critical value of f(x) = f'(c) = 0 or if f is not differentiable at c.
f(x) = 4(x-4)^(2/3)
f'(x) = (8/3)(x-4)^(-1/3)
f'(x) = 8/[3(x-4)^(1/3)]
f'(x) is not differentiable at x = 4 (division by zero)
Thus the value of A is 4.
Joe S.
asked 11/06/20Consider the function f(x)=−4(x−4)^2/3.
For this function there are two important open intervals: (−∞,A) and (A,∞) where A is a critical number. Find A
c is a critical value of f(x) = f'(c) = 0 or if f is not differentiable at c.
f(x) = 4(x-4)^(2/3)
f'(x) = (8/3)(x-4)^(-1/3)
f'(x) = 8/[3(x-4)^(1/3)]
f'(x) is not differentiable at x = 4 (division by zero)
Thus the value of A is 4.
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