Bradford T. answered 11/05/20
Retired Engineer / Upper level math instructor
If you plot the polar curve, you get an upside down cardoid. Looks line horizontal tangents touch the curve in only three places, at θ = π/2, 7π/6 and 11π/6.
So horizontal lines are at points when dy/dx = 0.
dy/dx = (dr/dθsin(θ) + rcos(θ))/(dr/dθcos(θ)-rsin(θ))
r = 1+sin(θ), dr/dθ = cos(θ)
So:
cos(θ)sin(θ) + (1+sin(θ))cos(θ) = 0 -> cos(θ)(2sin(θ)+1) = 0
cos(θ) = 0 at θ= π/2
sin(θ) = -1/2 at θ=7π/6 and 11π/6
This is the second selection.
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