x = 8 - t3 and y = t2 - 6t
dy/dx = (dy/dt) / (dx/dt) = (2t - 6) / (-3t2) = slope of tangent
dy/dx is undefined when -3t2 = 0. So, t = 0.
Point where dy/dx is undefined is (x,y) where x = 8-03 = 8 and y = 02 - 6(0) = 0
Joy C.
asked 11/05/20
For what value of t is the slope of the curve undefined for the graph defined by x = 8 - t3, y = t2 - 6t?
Type your answer in the space below to the nearest whole number
x = 8 - t3 and y = t2 - 6t
dy/dx = (dy/dt) / (dx/dt) = (2t - 6) / (-3t2) = slope of tangent
dy/dx is undefined when -3t2 = 0. So, t = 0.
Point where dy/dx is undefined is (x,y) where x = 8-03 = 8 and y = 02 - 6(0) = 0
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