The answer is simply T[(5,-3)]=5T[(1,0)]-3T[(0,1)]=5(2,5)-3(-1,6)=(10,25)+(3,-18)=(13,7). Also, since the basis e_{1}, e_{2} is mapped onto another basis of R^{2} namely, (2,5) and (-1,6) we have that the linear transformation T is 1-1 and onto R^{2}.
Sullivan J.
asked 11/04/20Linear Algebra, advanced mathematics
Okay, let e1 = (1,0), e2 = (0,1), y1 = (2,5), and y2=(-1,6). Let T: R2 →R2 be a transformation that maps e1 into y1 and maps e2 into y2. Find the image of (5, -3) under T. Is T onto? Is it One-to-one? Justify.
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