The derivative is x+2x ln x which is 1 when x = 1
Therefore, 1 = y/(x-1) and y = x -1 is the equation of the tangent.
Sophia C.
asked • 11/02/20Find an equation of the tangent line to the curve y = x2 ln x at (1, 0). Write your anser in slope-intercept form.
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