Patrick B. answered 11/02/20
Math and computer tutor/teacher
xy = 230
y = 230/x
A(x) = (x-6)(y-10)
= (x-6)(230/x - 10)
= 230 - 10x - 1380/x + 60
= 290 - 10x - 1380/x
0 = dA/dx = -10 + 1380x^(-2)
0 = -10x^2 + 1380
-1380/-10 = x^2
138 = x^2
sqrt(138) = x
which is APPROXIMATELY 11.747340124470730586968506365965
so then y = 230/x = 19.578900207451217644947510609941
Subtract 6 from x and 10 from y to get the max
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