Tyrone W.

asked • 10/30/20

Derivatives of Inverses #15

Suppose f is a one-to-one, differentiable function and its inverse function f^{-1} is also differentiable. One can show, using implicit differentiation (do it!), that

(f^{-1})'(x)=\frac{1}{f'(f^{-1}(x))}

Find (f^{-1})'(-4) if f(-2)=-4 and f'(-2)=2/7.


(f^{-1})'(-4) =

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