
Bradford T. answered 10/29/20
Retired Engineer / Upper level math instructor
From above
y' = (sin(x) -5y2)/3 = f(x,y)
f0 = f(.3,5) = (sin(.3)-5(5)2)/3 = 41.568
y(.6) = y(.3) + hf0 = 5+ (.3)(-41.568) = -7.47
f1 = (sin(.6)-5(-7.47)2)/3 =-92.82
y(.9) = y(.6) + hf1 = -7.47 + (0.3)(-92.82) = 35.3177 ≈ -35.318 The first choice