
Yefim S. answered 10/26/20
Math Tutor with Experience
We have V = 1/6abc under constrains 5/a + 5/b + 5/c = 1.We applying Lagrange Multipliers method
F(a,b,c) = 1/6abc - λ(5/a + 5/b + 5/c - 1); Fa = 1/6bc + 5λ/a2 = 0; Fb = 1/6ac + 5λ/b2 = 0; Fc = 1/6ab + 5λ/c2 = 0 and 5/a + 5/b + 5/c = 1. We have system of 4 equations with 4 variables a, b, c and λ
We have a2bc = b2ac = c2ab = - 30λ, from here a = b = c.
5/a + 5/a + 5/a = 1; a = 15, b = 15 and c = 15
Vmin = 1/6·153 = 562.5
To show that this is minimum, let take any different plane passing this point (5, 5, 5).For example:
x/20 + x/20 + x/10 = 1. so v = 1/6·20·20·10 = 6662/3 > 562.5