Patrick B. answered 10/25/20
Math and computer tutor/teacher
the derivative is
90x^8 + 7 x^50 y' + 350x^49 + 3y^2 y' = 0
given (1,1)
90 + 7y' + 350 + 3y' = 0
10y' + 440 = 0
y' = -44
B = y - mx = 1 - (-44)(1) = 45
y = -44x+45
Hanna S.
asked 10/25/20a. dy/dx=
b. Now, find the equation of the tangent line to the curve at (1, 1). Write your answer in
mx+b format. y=
Patrick B. answered 10/25/20
Math and computer tutor/teacher
the derivative is
90x^8 + 7 x^50 y' + 350x^49 + 3y^2 y' = 0
given (1,1)
90 + 7y' + 350 + 3y' = 0
10y' + 440 = 0
y' = -44
B = y - mx = 1 - (-44)(1) = 45
y = -44x+45
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