Daniel B. answered 10/25/20
A retired computer professional to teach math, physics
Let r(t) be an n-dimensional vector (r1(t), ..., rn(t)).
For convenience I will drop the variable (t) and write r = (..., ri, ...).
Then
|r|^2 = SUM(ri^2)
(|r|^2)' = SUM(2*ri*ri') = 2*r*r' = 0
Therefore |r|^2 is constant.