The width of the rectangle is 0.7 meters less than the length. The perimeter of a rectangle is 52.6 meters. Find the dimensions of the rectangle

Answer 1

P = W + L + W + P = 2W + 2L where P=perimeter, W=width and L=length

We don't immediately know W or L, but we have been given information that helps us figure it out.

From the question, let L = x, an unknown number. And so W = x - 0.7m. And P = 52.6m.

Hence 52.6 = 2(x - 0.7) + 2x

=> 52.6 = 2x - 1.4 + 2x = 4x - 1.4

=> 4x = 54

=> x = 13.5

The rectangle has dimensions of 13.5m x 12.8m.

Double-check? 13.5 + 12.8 = 26.3 and 26.3 x 2 = 52.6 = correct! And what units? Meters.