Find the area of the surface obtained by rotating the curve given by x(t)= 1/4t^2-1/2ln(t), y(t)=t, 1<_t<_2 about the x axis.

Question

I've gotten down to 2pi times the definite integral of t times the square root of ((t^4-2t+1)/(4t^2)+1). I don't know where to go from there. Thanks for any help.

Answer 1

Have a look at

https://tutorial.math.lamar.edu/classes/calcii/ParaSurfaceArea.aspx