9^{2x-1} = 27

(3^{2})^{2x-1} = 3^{3}

3^{4x-2} = 3^{3}

Graphing the exponents as y = 4x - 2 and y = 3, we get:

The solution is the intersection of these lines which occurs at x = 5/4

Kai N.

asked • 12dConsider this function 9^{2x-1} = 27. Using graphs of exponents, give a graphical interpretation of what it means to find the x values which satisfy the equation above.

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9^{2x-1} = 27

(3^{2})^{2x-1} = 3^{3}

3^{4x-2} = 3^{3}

Graphing the exponents as y = 4x - 2 and y = 3, we get:

The solution is the intersection of these lines which occurs at x = 5/4

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