
Basil Francis A.
asked 10/16/20Locate the critical points of the given function
Do the following:
a) Locate the critical points of the given function
f(x)=x^2/3 (x-4)
b) Use the first derivative test to locate the local maximum and minimum values
c) Identify the absolute minimum and maximum values of the function on the given interval
[-5,5]
INSTRUCTIONS: Fill in the missing numbers in order to determine the correct answers. Up to two decimal places only.
1. ) Critical points: x = ______and x = ____ / 5
2.) Local maximum at x = and f(0) = and Local minimum at x = 8/5 and f(8/5) ≈
3.) Absolute maximum value of f on [-5, 5] = __________
Absolute minimum value of f on [-5, 5] = __________
1 Expert Answer

Doug C. answered 10/21/20
Math Tutor with Reputation to make difficult concepts understandable
desmos.com/calculator/owjxc1yud8
Open the derivatives folder on the above graph to see ways to use Desmos to verify your derivative formulas.
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William W.
Please clarify the function. Is f(x) = (x^2)/(3(x-4)) or is f(x) = (x^2/3)(x-4) or ??? What exactly is in the numerator and what is in the denominator?10/17/20