
William W. answered 10/17/20
Experienced Tutor and Retired Engineer
Since f(x) = 4x2 - x, we can say that:
f(x+h) = 4(x + h)2 - (x + h)
f(x+h) = 4(x2 + 2xh + h2) - x - h
f(x+h) = 4x2 + 8xh + 4h2 - x - h
So f(x + h) - f(x) = (4x2 + 8xh + 4h2 - x - h) - (4x2 - x)
f(x + h) - f(x) = 4x2 + 8xh + 4h2 - x - h - 4x2 + x
f(x + h) - f(x) = 8xh + 4h2 - h
f(x + h) - f(x) = h(8x + 4h - 1)
So (f(x + h) - f(x))/h = h(8x + 4h - 1)/h = 8x + 4h - 1
And the limit as h approaches zero is 8x - 1