
William W. answered 10/16/20
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The chain rule says for h(x) = f(g(x)), then h’(x) = f ’(g(x)) • g’(x)
In this case f '(x) = cos(x) and g'(x) = 2x
So (f(g(x))' = f '(g(x))•g'(x) = cos(x2 - 9)•2x
Plugging in x = 3 we get (f(g(3))' = cos(32 - 9)•2(3) = cos(0)•6 = 1•6 = 6