The chain rule says for h(x) = f(g(x)), then h’(x) = f ’(g(x)) • g’(x)
In this case f '(x) = cos(x) and g'(x) = 2x
So (f(g(x))' = f '(g(x))•g'(x) = cos(x2 - 9)•2x
Plugging in x = 3 we get (f(g(3))' = cos(32 - 9)•2(3) = cos(0)•6 = 1•6 = 6
Cao N.
asked 10/16/20If and
, what is
?
The chain rule says for h(x) = f(g(x)), then h’(x) = f ’(g(x)) • g’(x)
In this case f '(x) = cos(x) and g'(x) = 2x
So (f(g(x))' = f '(g(x))•g'(x) = cos(x2 - 9)•2x
Plugging in x = 3 we get (f(g(3))' = cos(32 - 9)•2(3) = cos(0)•6 = 1•6 = 6
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.