Suppose that f(2) = −3, g(2) = 4, f '(2) = −2, and g'(2) = 1. Find h'(2). (a) h(x) = 2f(x) − 3g(x) , h(x) = f(x)g(x) , h(x) = f(x) g(x) , h(x) = g(x) 1 + f(x)

Answer 1

Please write the correct forms of these h(x) = f(x)g(x) , h(x) = f(x) g(x) , h(x) = g(x) 1 + f(x), so I could provide the answer.

So far the first two answers are -7 and -11.