Find an equation of the tangent line to the curve y = ex√x + 1 at the point (0, 1). Write your answer in slope-intercept form. cos x

Answer 1

y = (e^x)(x)^(1/2)+1

y' = e^x(x^(1/2)+(1/2)x^(-1/2)) = (e^x)(x)^(1/2)(1+(1/2)/x) = 0

1+(1/2)/x = 0

x = -(1/2)

m = -(1/2)

1 = -(1/2)0+b

b = 1

y = -(1/2)x=1