Stephen A.
asked • 10/10/20∫((16)/(x)-(11)/(10√x)dx
Bobosharif S. answered • 10/10/20
PhD in Math, MS's in Calulus
∫((16)/(x)-(11)/(10√x)dx = ∫(16)/(x)dx-∫(11)/(10√x)dx
= 16∫dx/x-(11/10)∫1/(√x)dx =16ln(x)-(11/10) 2 (√x) +C =16ln(x)-(11/5) (√x) +C, C is a constant,
Tom K. answered • 10/10/20
Knowledgeable and Friendly Math and Statistics Tutor
16 ln(x) - 11/5 √x + C
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