Find an equation of the line through (4, -3) with a slope of 3/4.

Question

 

I don't understand exactly what it is asking me for, please help. Thank you!

Answer 1

The equation of a line is in the form y = mx+b, where m is slope and b is y-intercept.

 

Your point is (4,-3) and slope is 3/4.  We substitute into the equation.

 

y = mx + b

-3 = (3/4)(4) + b

-3 = 3+b

-6 = b

 

Your equation of the line is

 

y = (3/4)x - 6

 

Answer 2

General line equation is y = mx +a

m = 3/4

y = (3/4)x + a

substitute (4,-3) for x and y

-3 = 3 + a, a= -6

So the line equation is y = (3/4)x -6