suppose h(x) =√3-2x^2. find two functions f and g such that (f°g) (x) =h(x)

Answer 1

An obvious choice would be f(x) = √(3 -x) and g(x) = 2x²

Then, f(g(x)) = √(3 - g(x)) = √(3 - 2x²), which equals h(x)