
Bobosharif S. answered 10/07/20
PhD in Math, MS's in Calulus
You are almost there, you have to exclude θ completely and have an equation that contains only x and y
this is correct x=sin2(θ)/y2.
Now think how to get rid of sin2(θ).
Alex S.
asked 10/07/20I believe I messed up somewhere along the way. I solved this as cosθ= 1/y and substituted into x to get x=sin^2(θ)/(1/y)^2. Simplifying to get x=y times sinθ. The website that our homework is through says this is incorrect. Any help is offered.
Bobosharif S. answered 10/07/20
PhD in Math, MS's in Calulus
You are almost there, you have to exclude θ completely and have an equation that contains only x and y
this is correct x=sin2(θ)/y2.
Now think how to get rid of sin2(θ).
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