integratethis equation

Question

∫ (7x^6+2x^(−2)) /x^4dx

from 3 to 7



Answer 1

∫₃ ⁷(7x⁶+2x⁻²) /x⁴dx=

= ∫₃ ⁷(7x^6-4+2x^−2-4)dx

= ∫₃ ⁷(7x²+2x⁻⁶)dx= =7 ∫₃ ⁷(x²dx+ +2∫₃ ⁷x⁻⁶dx =

=7x³/3|₃⁷ -2x^-7/7|₃⁷ =(7/3)(7³ -3³)-(2/7)(7^-7-3^-7)=..

Answer 2

that's

x^7 + 2/7x^7

at 7 that's

7^7 +2/7^7

at 3 that's

3^7 + 2/3^7

subtract them to get the integral from 3 to 7

7^7 + 2/7^7 - 3^7 - 2/3^7 =

Need a calculator at this point