Richard P. answered 10/04/20
PhD in Physics with 10+ years tutoring experience in STEM subjects
Since the slopes of the four line segments are all either +1 or -1, it is easy to locate the center of mass at the point (0,3), and determine that the shape is a square centered at that point.
The moments M_x and M_y through the CM will be equal. by the symmetry of a square.
M_x = 2 ∫ x2 [4 - 2x] dx with limits of integration 0 and 2. {That is twice the contribution from the right side of the square}
The integral is easy to evaluate giving M_x = 32/3