Yefim S. answered 10/02/20
Math Tutor with Experience
R(x) = (297 - 11x) (30 + 10x) = 8910 + 2640x - 110x2;
R'(x) = 2640 - 220x. To get maximum revenu we set R'(x) = 2640 - 220x = 0, so x = 2640/220 = 12
So max revenu Rmax = R(12) = 24750 if price = 30 + 120 = $150 per ticket
R''(x) = - 220 < 0 so we have max by second derivative test.