Find the equation of the linear function m that has m(-13)=7 and that is perpendicular to f(t)= -16/3t - 3

Question

Write the answer in slope-intercept form unless the answer is a vertical line, then type the answer in the form "t = #".

Answer 1

f'(t)=(16/3)t^-2 and at t=-13 the value of the derivative is 16/507

The slope of a line perpendicular to tangent of f(t) at this point is -507/16

The equation of the line required is -507/16 = (y-7)/(t+13)

I will leave it to you to "massage" this equation into point-slope form.