If we set u = 5 - 2sin(2x)
then du = -4cos(2x) dx
so dx = (-1 / 4cos(2x)) du
When you substitute u and du into the original equation, the cos terms will cancel out and simplify to an easy term to integrate.
∫ [cos(2x) / √(u)] * (-1 / 4cos(2x)) du = ∫ [ -1 / 4√u ] du
Your answer is D
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