Janelle S. answered 09/24/20
Penn State Grad for ME, Math & Test Prep Tutoring (10+ yrs experience)
Solve by trial and error. If we explore option D:
For k = 1: numerator = k = 1, denominator = k2 + 1 = 12 + 1 = 2
For k = 2: numerator = k = 2, denominator = k2 + 1 = 22 + 1 = 5
For k = 3: numerator = k = 3, denominator = k2 + 1 = 32 + 1 = 10
For k = 4: numerator = k = 4, denominator = k2 + 1 = 42 + 1 = 17
For k = 5: numerator = k = 5, denominator = k2 + 1 = 52 + 1 = 26
This will create the correct series, so your answer is D