
Yefim S. answered 09/23/20
Math Tutor with Experience
This volume V = ∫01π/2(e-x/2)2dx = - 1/16πe-2x01 = 1/16π - 1/16πe-2 = π/16(1 - 1/e2).
Right answer is 2nd from the top.
Lilah B.
asked 09/23/20The base of a solid in the region bounded by the graphs of y = e-x y = 0, and x = 0, and x = 1. Cross sections of the solid perpendicular to the x-axis are semicircles. What is the volume, in cubic units, of the solid? (4 points)
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Yefim S. answered 09/23/20
Math Tutor with Experience
This volume V = ∫01π/2(e-x/2)2dx = - 1/16πe-2x01 = 1/16π - 1/16πe-2 = π/16(1 - 1/e2).
Right answer is 2nd from the top.
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