Suppose F(x)=f(x)g(2x). If f(1)=3, f’(1)=3, g(2)=2, g’(2)=5. Find F’(1). Find the derivative of g(2x) at x=1

Answer 1

apply the chain rule

F'(x) = (f(x)g(2x))' = f'(x)g(2x) + f(x)(g(2x))' = f'g + 2fg'

just substitute in values now.

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