Calculus Please Help!

Question

For an object whose velocity in ft/sec is given by v(t) = -2t² + 4, what is its distance travelled, in feet, on the interval t = 0 to t = 2 secs? (5 points)

Answer Choices:

	4.876
	2.667
	9.752
	2.438

Answer 1

v(t) = -2t² + 4

s(t) = ∫v(t) = (-2/3)t³ + 4t + C

s(2) - s(0) = [(-2/3)(2)³ + 4(2) + C] - [(-2/3)(0)³ + 4(0) + C] = [-16/3 + 8 + C] - [0 + C] = 2.667

Your answer is B