A = grade of "A"
B = grade of "B"
C = grade of "C"
P(B) = 19/70 = 0.2714
The probability that the student got a "B" on the test is 0.2714.
P(Female ∩ B) = 6/70 = 0.08571
The probability that the student is a female and got a "B" on the test is 0.08571
P(Female ∪ C) = P(Female) + P(C) - P(Female ∩ C) = (26/70) + (18/70) - (4/70) = 40/70 = 4/7 = 0.5714
The probability that the student is either a female or got a "C" on the test is 0.5714.
P(Male|A) = P(Male ∩ A) ÷ P(A) = (17/70) / (33/70) = (17/70)*(70/33) = 17/33 = 0.5152
The probability that the student who got a "A" on the test is a male is 0.5152.