2C4H10 + 13O2 → 8CO2 + 10H2O
In the balanced equation above
There are 8 Carbons 20 Hydrogens and 26 Oxygens on one side and 8 Carbons 16 Oxygen and 20 Hydrogens and 10 Oxygens totalling again 8 Carbons, 26 Oxygens and 20 Hydrogens
Johhny J.
Solving by RREF
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09/23/20
Ha R.
There are ... / on one side ... / totalling ...
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03/18/21
Brenda D.
tutor
With your three elements C, H and O you need do the following 8 steps
Identify the equation to balance. (that is given in your question)
Identify the elements.(Also given in your question)
Set up the vector equation.
Set the equation to 0 and obtain the augmented matrix.
Row-reduce to reduced row-echelon form.
Reparameterize the free variable and solve for the variables.
Substitute an appropriate value for .
Substitute the coefficients, they will be fractions with a common multiple of -10(to give 2, 13,= 8, 10) into the chemical equation.
The chemically balanced equation shows what kind of numbers you should get after going through the process above. You can look this up on the internet if you need a longer example. Hope this helps. The balance chemical shows what you should end up after going through your matrix
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03/18/21
Brenda D.
tutor
Here is an address that you can check out for your matrix
https://www.emathhelp.net/calculators/linear-algebra/reduced-row-echelon-form-rref-caclulator/.
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03/18/21
Johhny J.
I want this to be solved in a matrix09/23/20