Kathy P. answered 09/17/20
Mechanical Engineer with 10+ years of teaching and tutoring experience
Q(0) = Ae^(0)
15000 = A ==>. Q(x) = (15000)e^(-kx)
Q(10) = (15000)e^(-k*10)
9000 = (15000)e^(-10k)
9/15 = e^(-10k)
3/5 = e^(-10k)
ln(3/5) = -10k
k = ln(3/5) / (-10)
k = ln(5/3) / (10) = 0.05108
Therefore: Q(x) = (15000)e^(-0.05108 x)