Reza F. answered 09/16/20
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Physics, Math (AP, HS, Colledge) , and Electrical Engineering Tutor
f'(x) = [ (6x+2)' * (3x+4) - (6x+2)*(3x+4)' ] over (3x+4)^2. Therefore,
f'(x) = [ (6 * (3x+4) - (6x+2)*3 ] over (3x+4)^2
f'(x) = 18 over (3x+4)^2
f'(4) = 18 over (3*4+4)^2 = 18 over 256
f'(4) = 0.07