Michael H.
asked 02/12/15someone please help
I have to sketch a graph for the rational equation with all asymptotes included where are the asymptotes and what points work for drawing the graph
F(x)=X^2-4/x^2-3x+2
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1 Expert Answer
Michael J. answered 02/12/15
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Effective High School STEM Tutor & CUNY Math Peer Leader
Vertical Asymptotes
Set the denominator equal to zero.
x2-3x+2 = 0
(x-2)(x-1) = 0
x = 1 , x = 2
Vertical asymptote is x=1 and x=2
Horizontal Asymptotes
We focus on the coefficients of the term with the highest degree. In this function, the term with the highest degree in the numerator is x2 and the term with the highest degree in the denominator is x2. Since the degree of the numerator and denominator are the same, we divide their coefficients. These are noted in bold.
(x2-4)/(x2-3x+2)
Therefore, the horizontal asymptote is 1.
Graph this function to check.
Michael H.
F(x)=X^2-4/x^2+3x+2 I apologize I didn't realize it was the wrong symbol the equation should have been + 3x.
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02/12/15
Michael J.
In the case,
Vertical Asymptote
(x2+3x+2) = 0
(x+1)(x+2)= 0
x = -1 , x = -2
Your vertical asymptotes are x = -1 and x = -2
Horizontal Asymptote remain the same.
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02/13/15
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Michael H.
02/12/15