Then expression you have posted is continuous; therefore, the limit is 0.
Alternatively,9-6h+h2-9 = 6h + h2 which goes to 0 as h goes to 0
Brigitte S.
asked 09/13/20Evaluate the limit, if it exists. (If an answer does not exist, enter DNE.)
| lim h → 0 (−3 + h)2 − 9 |
| h |
Then expression you have posted is continuous; therefore, the limit is 0.
Alternatively,9-6h+h2-9 = 6h + h2 which goes to 0 as h goes to 0
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