Tom K. answered 09/09/20
Knowledgeable and Friendly Math and Statistics Tutor
If x = t2 - 9 = (t - 3)(t-3), x > 0 for (-∞, -3) ∪ (3, ∞) and x < 0 for (-3, 3)
If y = (t2 - 8t) = t(t - 8), y > 0 for (-∞, 0) ∪ (8, ∞) and y < 0 for (0, 8)
Thus, consider the intervals (-∞, -3), (-3, 0), (0, 3), (3, 8), and (8, ∞)
On (-∞, -3) ∪ (8, ∞), x > 0 and y > 0, so we are in Quadrant I
On (-3, 0), x < 0 and y > 0, so we are in Quadrant II
On (0, 3), x< 0 and y < 0, so we are in Quadrant III
On (3, 8), x > 0 and y < 0, so we are in Quadrant IV.