Consider the curve parameterized by 𝑐(𝜃)=(sin3(𝜃),cos(𝜃)). Compute 𝑑𝑦/𝑑𝑥 at the point (2sqrt4,2sqrt2).

Answer 1

x(θ) = sin(3θ) therefore dx/dθ = 3cos(3θ)

y(θ) = cos(θ) therefore dy/dθ = -sin(θ)

so dy/dx = (dy/dθ)/(dx/dθ) = - sin(θ)/(3cos(3θ))

Unfortunately, I can't figure out what the point in question is, from the infor given...