
Mike D. answered 09/07/20
Effective, patient, empathic, math and science tutor
Dazzmine
There are 15 basketballs, 10 of which are not brand B.
So probability (ball isn't brand B) = 10 / 15 = 2 / 3
Mike
Dazzmine A.
asked 09/07/20A total of 15 basketballs, including 6 brand A, 5 brand B, and 4 other brand-name balls are on a basketball court. Barry closes his eyes and arbitrarily picks up a ball from the court. What’s the probability that the ball selected isn’t a Brand B ball?
Mike D. answered 09/07/20
Effective, patient, empathic, math and science tutor
Dazzmine
There are 15 basketballs, 10 of which are not brand B.
So probability (ball isn't brand B) = 10 / 15 = 2 / 3
Mike
Cheyenne B. answered 09/07/20
University Student looking to Tutor
There are 15 balls in total. 6 are Brand A, 5 are Brand B, 4 are Brand C.
First add up Brand A and Brand C balls to figure out how many are NOT Brand B.
This gives us 10 out of 15 balls that are not Brand B.
Our fraction is (10/15).
Now, simplify that to the smallest possible terms.
What factor goes into both 10 AND 15? The number 5.
Divide both the numerator and the denominator by 5 which gives you (2/3). This is your final answer
6+5+4 = 15
6+4 = 10
10/15
(10/5) / (15/3)
2/3
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