Mark M. answered 09/05/20
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
f'(x) = slope of tangent line at the point (x, f(x))
f'(x) = limh→0 [(f(x+h) - f(x)) / h] = limh→0 [(6(x+h)2 +4(x+h) + 5 - (6x2 + 4x + 5))/h] =
limh→0 [(12xh +6h2 + 4h)/h] = limh→0 [h(12x + 6h + 4) / h] = limh→0(12x + 6h + 4) = 12x + 4
So, f'(1) = 16.