Tom K. answered 09/02/20
Knowledgeable and Friendly Math and Statistics Tutor
a^3 + b^3 = (a+b)(a^2 - ab + b^2)
Thus, (x+4)/(x^3+64) = (x+4)/((x+4)(x^2-4x + 16)) = 1/(x^2-4x+16) for x not equal to -4
Thus, lim x -> -4 1/(x^2 - 4x + 16) = 1/((-4)^2-4(-4)+16) = 1/48