Yefim S. answered • 08/31/20
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y' = lim as h→01/{[2(x + h) + 3] - 1/(2x + 3)}/h = lim as h→0 {(2x + 3 - 2x - 2h - 3)/[(2x + 3)(2x + 2h + 3)h]} =
-2/(2x + 3)2
Chris J.
asked • 08/31/20For y = 1/(2x + 3) use the limit definition of derivative to calculate y .
For y = 1/(2x + 3) use the limit definition of derivative to calculate y' .
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2 Answers By Expert Tutors
Victoria V. answered • 08/31/20
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Please see video
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