Inactive Tutor answered 08/21/20
Tutor
New to Wyzant
y = mx + b
m = (y2 - y1 ) / (x2 -x1 )
m = (3-1)/ (-1-1) = 2/-2 = -1
y-y0 = mx + b
y-1 = -x + 1
y = -x + 2
test:
y = -(-1) + 2
y = 1 + 2
y = 3
Alex C.
asked 08/21/20Write the answer in standard form
Inactive Tutor answered 08/21/20
y = mx + b
m = (y2 - y1 ) / (x2 -x1 )
m = (3-1)/ (-1-1) = 2/-2 = -1
y-y0 = mx + b
y-1 = -x + 1
y = -x + 2
test:
y = -(-1) + 2
y = 1 + 2
y = 3
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