Richard D. answered 08/21/20
Put in the work, don't give up.
We want to put this in to our matrix. since, we want to have R3 then we need to have our 3 vectors span that region. And so we need to solve for k so that all three vectors are Linearly Independent.
so,
A = [ 6 -5 2 ]
[ -1 3 4 ]
[ 0 7 k ]
step 1: sove for det (a) do the cross product to solve for each of the smaller squares.
det(A) = 6 * (3k-28) -(-5)(-k) + 2(-7)
= 18k - 168 - 5k -14
= 13k-182
step 2: solve for k so
13k = 182
k = 14
V1, V2, V3 are Linearly Independent if Det(a) does not equal k=14.
Thus, we can say that V1, V2, V3 form a basis for R3 iff. k does not equal 14.