Sava D. answered 08/19/20
Math master degree tutor with good understanding of calculus
(Calculus answer)
The position function for the problem is with
vo = 65 and so = 0.
The function
s(t) = - 16 t2 +65 t + 0
The first derivative is zero when we reach max height.
s`(t) = - 32 t +65.
-32 t + 65 = 0
t = 65/32 sec.
max height is
s(65/32) =66.01 feet (rounded).
Alternatively, you set s(t) = 0 and solve for t. The max height is the average for the two zeros you found.