
Yefim S. answered 08/19/20
Math Tutor with Experience
(a) Marginal cost function MC(x) = C'(x) = 0.06x2 - 10.
(b) If x = 70 then MC(70) = 0.06·702 - 10 = $284 per item
(c) ΔC = C(71) - C(70) = 6948.22 - 6660 = $288.22, so ΔC ≈ MC(70)
Joaquin E.
asked 08/19/20If the current production level is x items with cost C(x), then the cost of computing h additionial items is C(x+h). The average cost of those h items is (C(x+h)−C(x))h . As we analyze the cost of just the last item produced, this can be made into a mathematical model by taking the limit as h→0, i.e. the derivative C′(x). Use this function in the model below for the Marginal Cost function MC(x).
Problem Set question:
The cost, in dollars, of producing x units of a certain item is given by
C(x)=0.02x3−10x+500.
(a) Find the marginal cost function.
MC(x)=
__________
(b) Find the marginal cost when 70 units of the item are produced.
The marginal cost when 70 units are produced is $____________.
(c) Find the actual cost of increasing production from 70 units to 71 units.
The actual cost of increasing production from 70 units to 71 units is $____________.
Yefim S. answered 08/19/20
Math Tutor with Experience
(a) Marginal cost function MC(x) = C'(x) = 0.06x2 - 10.
(b) If x = 70 then MC(70) = 0.06·702 - 10 = $284 per item
(c) ΔC = C(71) - C(70) = 6948.22 - 6660 = $288.22, so ΔC ≈ MC(70)
Mark M. answered 08/19/20
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
C(x) = 0.02x3 - 10x + 500
Marginal cost function = C'(x) = 0.06x2 - 10
Marginal cost when x = 70 is C'(70) = $284
Actual cost of increasing production from 70 to 71 units is C(71) - C(70) = 6948.22 - 6660 = $288.22
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