C H. answered 08/19/20
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Let us call [1 6 2], [0 1 -7], [0 0 1] by b1, b2, b3, respectively. To find the coordinate vector [a b c] of x in Basis B, we need to find a,b,c, satifying
x = ab1+bb2+cb3.
So we have a system of equations
-2 = a + 0 + 0
-2 = 6a + b + 0
-3 = 2a - 7b + c.
We have a=-2, b=10, c = 71.